Australian Open 2019: Alexander Zverev loses to Milos Raonic in fouth round

Ruben Hill
January 21, 2019

Alexander Zverev suffered a complete meltdown on the Rod Laver Arena to provide one of the most memorable moments of the Australian Open thus far as he was beaten by Milos Raonic in straight sets.

The big-serving Canadian had his serve broken in the opening game but responded by winning the next eight games to go up a break in the second set.

Raonic ultimately won six games on the spin to take the first set, converting three of his 12 break-point opportunities as Zverev sent down three double faults.

Upset about how badly things were going in his match, Zverev sat down in his sideline chair and destroyed his racket by whacking it against the ground eight times - and then tossing it aside.

Zverev, who lost the first set 6-1 in unusual circumstances, was broken for the second time in the second set and turned his anger to his racquet as he sat down at 4-1.

Raonic will play the victor of Borna Coric and Lucas Pouille's round of 16 clash in the quarters. After falling behind 4-1 in the second, Zverev had just about enough.

Raonic could smell blood, and broke Zverev once again to take a two-set lead.

A tie-break swiftly followed after two holds to love, and though momentum swung this way then that, it was Raonic who bounced back from 3-1 and 4-2 down to seal it 7-5.

Other reports by Click Lancashire

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